Question

I need help with this question . Only part (b)

Answer 1

Given:

The mass of the pendulum, m=1.29 kg

The length of the simple pendulum, L=0.830 m

The period of the pendulum, T=1.809 s

To find:

(b) The spring constant of the spring so that the period of the oscillation of the spring will be T.

Step-by-step explanation:

The period of oscillation of a spring-mass system is given by the equation,

`T=2\pi\sqrt{(m)/(k)}`

On rearranging the above equation,

`\begin{gathered} T^2=4\pi^2((m)/(k)) \\ \Rightarrow k=(4\pi^2m)/(T^2) \end{gathered}`

On substituting the known values,

`\begin{gathered} k=(4\pi^2*1.29)/(1.809^2) \\ =15.56\text{ N/m} \end{gathered}`

Final answer:

The spring constant of spring is 15.56 N/m