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What mass of krypton gas is in 4.50 L at SATP?

What mass of krypton gas is in 4.50 L at SATP?-example-1

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Answer

m = 15.2 g

Step-by-step explanation

Given:

Volume = 4.50 L

At SATP, meaning

Temperature = 25 °C = 298 K

Pressure = 101.325 kPa = 1 atm

Volume of 1 mole = 24.4651 L

We know R = 8.314m^3-Pa-/mol-K^2 = 0.08206 L.atm/mol.K

Solution

To solve this problem we will use the ideal gas law

PV = nRT

Step 1: Solve for number of moles (n)

n = PV/RT

n = (1 atm x 4.50 L)/(0.08206 L.atm/mol.K x 298 K)

n = 0.184 mol

Step 2: Now that we have the number of moles, we can convert to mass

Molar mass of Krypton gas = 83.7980 g/mol

m = n x M where m is the mass, n is the moles and M is the molar mass

m = 0.184 mol x 83.7980 g/mol

m = 15.4 g which is close to 15.2 g

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