Question

Write the equation y2 − 12y − 8x + 20 = 0 in vertex form.the quantity(y − 6)2 = 8times the quantity(x + 2) the quantity(y + 6)2 = 8times the quantity(x − 2) the quantity(x − 6)2 = 8times the quantity(y + 2) the quantity(y + 2)2 = 8times the quantity(x − 6)

Answer 1

`(y-6)^2=8(x+2)`

Explanation:

We have the following equation

`y^2-12y-8x+20=0`

We convert it to its vertex form like this:

`\begin{gathered} 8x=y^2-12y+20 \\ \text{ we complete square} \\ 8x=y^2-12y+20+(-6)^2-(-6)^2 \\ 8x=(y-6)^2-16 \\ 8x+16=(y-6)^2 \\ (y-6)^2=8(x+2) \end{gathered}`