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the figure Shown is the base of a right solid that is 10 meters high corners that look square are square find the latter will surface of the solid dimensions are in metres

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let's find the area by parts

red is the first part

we need the area of the red square an substract the mid-circle area

square is A=bxh

so A=2x4=8

the area of the circle is A=pi x r2

so the area of the circle is A=pi x 4 and the middle is 2pi

the total red area is


\begin{gathered} Ar=8-2\pi \\ \end{gathered}

green part

te area is A=bxh, the heigth is 4 like the diameter of the circle and the base is 8 less 2 (of the radius) and less 4(of the base

the figure Shown is the base of a right solid that is 10 meters high corners that-example-1
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