To answer this question we will use the following slope-point formula for the equation of a line:

Therefore, the equation of the line that has a slope of 3 and passes through (2,2) is:

Simplifying the above result we get:

Adding 2 to the above equation we get:

From the last equation, we get that the y-intercept of the line is (0,-4).
Since the graph of the line also passes through (2,2) we get that its graph is:
Answer: