We graph it as follows:
We will have that a solution for both systems is found at the intersection.
*One of the solutions can be 10 yards of blue fabric and 1 yard of green fabric. [Theare are multiple solutions for the system] //We also know that the solutions are all positive [Since we are talking about quantities].
*Another solution can be 6 yards of blue fabric and 4 yards of green fabric.
**We can determine they are solutions since they are the intersections of integers that are contained at the intersection of solutions for the inequalities.
***The solutions given replaced in the equations:
*First set.


*Second set:

