Question

Solve the system.—x2 + y2 = 16.y + 4 = x2=(-2.65, [?]) (0,[ ] (2.65, [ ])

Answer 1

Given the system of equations:

`\begin{cases}x^2+y^2=16 \\ y+4=x^2\end{cases}`

As shown in the figure, there are 3 points that are the solutions to the system

For each point given the value of x

So, we will substitute with (x) to find (y)

From the second equation:

`y=x^2-4`

substitute with x = -2.65, 0, 2.65

`\begin{gathered} x=-2.65\rightarrow y=(-2.65)^2-4=3 \\ x=0\rightarrow y=(0)^2-4=-4 \\ x=2.65\rightarrow y=(2.65)^2-4=3 \end{gathered}`

So, the answer will be:

`\begin{gathered} (-2.65,3) \\ (0,-4) \\ (2.65,3) \end{gathered}`