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Pythagorean Theorem:a? + b2 = c2 Re-write the formula solving for b?.

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The Pythagorean Theorem states the following:


a^2+b^2=c^2

Where "c" represents the hypotenuse of the Right triangle (which is a triangle that has an angle that measures 90 degrees), and "b" and "c" are the legs of the triangle.

To rewrite the formula solving for "b", you can follow the steps shown below:

1. Apply the Subtraction property of Equality by subtracting a^2 from both sides of the equation:


\begin{gathered} a^2+b^2-(a^2)=c^2-(a^2) \\ b^2=c^2-a^2 \end{gathered}

2. Now you must apply square root to both sides of the equation:


\begin{gathered} \sqrt[]{b^2}=\sqrt[]{c^2-a^2} \\ b=\sqrt[]{c^2-a^2} \end{gathered}

Because remember that:


\sqrt[n]{m}^n=m

Therefore, the formula solved for "b", is:


b=\sqrt[]{c^2-a^2}

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