Question

I am supposed to factor this expression. I came up with (g-3)(g+3)

Answer 1

The expression is given to be:

`g^2-9`

Rewrite the term:

`9=3^2`

Therefore, the expression becomes:

`g^2-3^2`

Apply the difference of two squares formula:

`x^2-y^2=\left(x+y\right)\left(x-y\right)`

Therefore, the expression becomes:

`g^2-3^2=\left(g+3\right)\left(g-3\right)`

ANSWER

`g^2-9=\left(g+3\right)\left(g-3\right)`