Question

1. A gas has a Volume of 10 L and a temp of 200 K. If the volume increases to 20 L, what is the new temp?

Answer 1

For this question we can use the formula provided from Charles's Law, which is:

V1/T1 = V2/T2

We have:

V1 = 10 Liters

T1 = 200 K

V2 = 20 L

T2 = ?

Now we add the values to the formula:

10/200 = 20/T2

0.05 = 20/T2

T2 = 400 K