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2 votes
How much time will be needed for $32,000 to grow to $33,467.27 if deposited at 3% compounded quarterly?

User Munawwar
by
8.3k points

1 Answer

4 votes

We need the time t in the compound interest formula:


A=P(1+(r)/(n))^(nt)

Then, if we move P to the left hand side, we get


(A)/(P)=(1+(r)/(n))^(nt)

If we apply logarithm in both sides, we obtain


\log (A)/(P)=nt\cdot\log (1+(r)/(n))

therefore, the time is given by


t=(\log (A)/(P))/(n\cdot\log (1+(r)/(n)))

In our case A= $33467.27 (Amount), P=$32000 (Principal), n=0.03 (interest rate) and n=4 (quarterly interest).

By substituting these values into the last formula, we have


t=(\log (33467.27)/(32000))/(4\cdot\log (1+(0.03)/(4)))

which gives


t=(\log 1.04585)/(4\cdot\log 1.0075)

the, the time is


\begin{gathered} t=(0.04482)/(0.02988) \\ t=1.5 \end{gathered}

that is, the time will be equal to 1.5 years.

User Haojen
by
8.1k points
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