The line:
![-2x+3y=-4](https://img.qammunity.org/2023/formulas/mathematics/college/bwiltnq2vuzpm79goxqume7lob66hptjkb.png)
can be written as:
![\begin{gathered} -2x+3y=-4 \\ 3y=2x-4 \\ y=(2)/(3)x-(4)/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/irzytrt2ci1v4olcdx68d6y83olo5ms9nx.png)
from this form we notice that its slope is 2/3.
We know that two lines are parallel if and only if their slopes are equal, this measn the lie we are looking for has slope 2/3 also.
Once we know the slope of the second line and since we know a point of it we can use the equation of a line:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
Plugging the values we have that the equation we are looking for is:
![y-3=(2)/(3)(x-1)](https://img.qammunity.org/2023/formulas/mathematics/college/o703a2uozio9feayy2jz1d0iqt36vooyz4.png)