Given:
There are given the expression:
![(x-10y)^7](https://img.qammunity.org/2023/formulas/mathematics/college/rvzcnrogzh7ig4p29alyhpw2ugkq5i1f44.png)
Step-by-step explanation:
According to the question:
We need to find the 4th term in the expansion.
So,
From the given expression:
![(x-10y)^(7)](https://img.qammunity.org/2023/formulas/mathematics/college/qvm91s59ktwoiwj29muc22l9ezich9y1b7.png)
To find the 4th expansion, we will use the binomial theorem:
So,
From the binomial expansion:
![(a+b)^n=\sum_{i\mathop{=}0}^n(n,i)a^(n-i)b^i](https://img.qammunity.org/2023/formulas/mathematics/college/8nd9r8jk3omcun0855x3o434x4klu5k93q.png)
Then,
Use the above formula in the given expression:
So,
From the given expression:
![(x-10y)^7=\sum_{i\mathop{=}0}^n(7,i)x^(7-i)(-10y)^i](https://img.qammunity.org/2023/formulas/mathematics/college/tv2o6llv7ymoosr7oly7innq88ti8lzk45.png)
Then,
![(x-10y)^7=(7!)/(0!(7-0)!)x^7(-10y)^0+(7!)/(1!(7-1)!)x^6(-10y)^1+(7!)/(2!(7-2)!)x^5(-10y)^2+(7!)/(3!(7-3)!)x^4(-10y)^3](https://img.qammunity.org/2023/formulas/mathematics/college/13spssh4z9gth14c0n27nzkigsu72iigwu.png)
Then,
![\begin{gathered} (x-10y)^(7)=(7!)/(0!(7-0)!)x^(7)(-10y)^(0)+(7!)/(1!(7-1)!)x^(6)(-10y)^(1)+(7!)/(2!(7-2)!)x^(5)(-10y)^(2)+(7!)/(3!(7-3)!)x^(4)(-10y)^(3) \\ (x-10y)^7=x^7-70x^6y+2100x^5y^2-35000x^4y^3 \end{gathered}]()
So,
The 4th term of the given expansion is shown below:
![-35000x^4y^3](https://img.qammunity.org/2023/formulas/mathematics/college/ee8r485bdj27hynw4fhigl21f10rpxdrbd.png)
Final answer:
Hence, the correct option is B.