177k views
2 votes
What is the value of x to the nearest tenth on problem 6

What is the value of x to the nearest tenth on problem 6-example-1

1 Answer

2 votes

ANSWER:

x = 15

Explanation:

We can calculate the value of x, with the help of the Pythagorean theorem, we obtain the following equation:


\left(x+10\right)^2=x^2+20^2

We solve for x:


\begin{gathered} \left(x+10\right)^2=x^2+400 \\ \\ x^2+20x+100=x^2+400 \\ \\ x^2-x^2+20x=400-100 \\ \\ 20x=300 \\ \\ x=(300)/(20) \\ \\ x=15 \end{gathered}

The value of x is equal to 15

User Klonq
by
5.7k points