Y = x {}^(2) + 8x + 16what is the vertex

Question

`y = x {}^(2) + 8x + 16`what is the vertex

Answer 1

Vertex: (-4, 0)

Axis of Symmetry: x = -4

Maximum Value: Does Not Exist

Minimum Value: y = 0

Step-by-step explanation:

The vertex form of an equation is

`y=a(x-h)^2+k`

where the coordinates of the vertex are

`V=(h,k)`

Tofind the vertex of the parabola, we first convert the equation to the vertex form.