Question

Graph the parabola Y = X^2 + 6x +13 Play five points on a parabola the vertex two points to the left of the vertex and two points to the right of the vertex then click on the graph a function button

Answer 1

Given:

`y=x^2+6x+13`

To plot 5 points on the parabola:

The given equation can be written as,

`\begin{gathered} y=x^2+6x++3^2-3^2+13 \\ y=(x+3)^2-9+13 \\ y=(x+3)^2+4 \end{gathered}`

Therefore, the vertex of the parabola is (-3, 4).

Put x=-2, we get y=5. So, the point is (-2, 5).

Put x=-1, we get y=8. So, the point is (-1, 8).

Put x=-4, we get y=5. So, the point is (-4, 5).

Put x=-5, we get y=8. So, the point is (-5, 8).

So, the graph is,