Calculate the [OH-] in a solution that has a pH of 3.08. a. 1.2x10-9 b. 8.3x10-3 C. 1.2x10-11 d. 8.3x10-4

Pmf asked Nov 2, 2022

123,294 views

0 votes

Calculate the [OH-] in a solution that has a pH of 3.08.

a. 1.2x10-9
b. 8.3x10-3
C. 1.2x10-11
d. 8.3x10-4

Pmf asked Nov 2, 2022

by Pmf

3.0k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

24 votes

Answer:

C. 1.2 x 10^-11

Step-by-step explanation:

pOH = 14 - pH = 14 - 3.08 = 10.92

[OH-] = 10^-pOH = 10^-10.92 = 1.2 x 10^-11

3.1k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers