Question

The y component of a vector R of magnitude k = Bcm shown in the figure below is Ky = +6 cm. What is the direction of this vector (The angle 8 that makes K with the x axis)?

Answer 1

Given

The y-component of vector K is

`K_y=6\text{ cm}`

The magnitude of vector K is , K=8 cm

To find

The angle

`\theta`

Step-by-step explanation

Resolving K along its y-component we have,

`\begin{gathered} K_y=Ksin\theta \\ \Rightarrow6=8sin\theta \\ \Rightarrow sin\theta=(3)/(4) \\ \Rightarrow\theta=48.59\text{ }^o \end{gathered}`

Conclusion

The angle made with the x-axis is

`48.59^o`