Given the graph of the Direct Variation, you can identify this point:
![\mleft(2,4\mright)](https://img.qammunity.org/2023/formulas/mathematics/college/hvqcpfd0frxsp39eesmkt34bv7148izrq6.png)
By definition, the equation of a Direct Variation has this form:
![y=kx](https://img.qammunity.org/2023/formulas/mathematics/college/zfnjlk9kn7jg7cyy0nlnepmsiaxj3b2oge.png)
Where "k" is the Constant of Variation.
In this case, knowing the point shown before, you can set up that:
![\begin{gathered} x=2 \\ y=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/79n53lj5tqof25ewqzbzj5p59n9so484b1.png)
Now you can substitute these values into the equation and solve for "k":
![\begin{gathered} 4=k(2) \\ \\ (4)/(2)=k \\ \\ k=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vr6rl7nsehtu22e55ztb2j4b83zxq5dju4.png)
Therefore, the equation that represents the line given in the exercise is:
![y=2x](https://img.qammunity.org/2023/formulas/mathematics/high-school/gehxm55opy2qzcw9pvonc2nzrebkjsukj6.png)
Since you need to find the value of "y" when:
![x=-15](https://img.qammunity.org/2023/formulas/mathematics/college/8qn80d1j8k879tgvdj4cw2j8j2dkhfza32.png)
You need to substitute that x-value into the equation and evaluate:
![\begin{gathered} y=2(-15) \\ y=-30 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hpfenpwc0wkqb1k6gwp9pqpg6cd4xktwba.png)
Hence, the answer is: Option A.