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Of 14 possible books, you plan to take 5 with you on vacation. How many different collections of 5 books can you take?

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Since the problem does not take the order into account this is a combination problem.

A combination is given by:


_nC_k=(n!)/(k!(n-k)!)

Then in this case we have:


_(14)C_5=(14!)/(5!(14-5)!)=2002

Therefore there are 2002 different collections of five books

User Tdelepine
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