we have the equation

Remember that
If an ordered pair is on the graph of the given function, then the ordered pair must satisfy the given function
Verify each option
N 1
(0,1)
x=0, y=1
Is not true, because the log of zero is undefined
N 2
(1,1/2)
x=1, y=1/2
Is not true, because the log of 1 is zero
N 3
(1/2,1)
![y=\operatorname{\log}_{(1)/(2)}(1)/(2)=1]()
Is true
therefore
The answer is (1/2,1)