Question

Find an equation for the line below. Points -6,2 and 4,-4

Answer 1

Given :

We have the points: (-6, 2), (4, -4)

The equation of a line given two points can be found using the formula:

`(y-y_1)/(x-x_1)\text{ = }(y_2-y_1)/(x_2-x_1)`

Substituting we have:

`\begin{gathered} \frac{y\text{ - }2}{x-(-6)}\text{ = }(-4-2)/(4-(-6)) \\ (y-2)/(x+6)=(-6)/(10) \\ \text{Cross}-\text{Multiply} \\ 10(y-2)\text{ = -6(x + 6)} \\ 10y\text{ - 20 = -6x - 36} \\ \text{Collect like terms} \\ 10y\text{ = -6x - 36 + 20} \\ 10y\text{ = -6x - 16} \end{gathered}`

Answer: 10y = -6x - 16