Given,
Mass of the cars, m₁=m₂=3000 kg
The distance between the cars, r=2m
From the universal law of gravitation,
![F=(Gm_1m_2)/(r^2)](https://img.qammunity.org/2023/formulas/physics/college/o17slql8zhfxufgswvdbl9021lqzu8lnir.png)
Where G is the gravitational constant. The value of G is 6.67×10⁻¹¹ N·m²/kg²
On substituting the known values in the above equation,
![F=(6.67*10^(-11)*3000*3000)/(2^2)=1.05*10^(-4)\text{ N}](https://img.qammunity.org/2023/formulas/physics/college/nfgg38f3m2w53nm0wl3wv07y4ilx6363f4.png)
Therefore the force between the cars is 1.05×10⁻⁴ N