Question

Find the equation of the line that is parallel to y=4x+1 and contains the point (1,1)

Answer 1

The given equation is:

`y=4x+1`

Notice that the slope of the given equation is 4.

Recall the slopes of parallel line are equal.

Therefore the slope of the required line is 4.

Since the slope of the required line is 4 and it is given that the line contains the point (1,1)

Then the equation of the line using Point-Slope Form is:

`\begin{gathered} y-1=4(x-1) \\ y-1=4x-4 \\ y=4x-4+1 \\ y=4x-3 \end{gathered}`

Therefore the required equation is:

`y=4x-3`