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5. Solve the problem,Two pieces of production equipment for a factory were purchased for a total of$2000. If one piece cost $810 more than the other find the price of the lessexpensive piece of equipmentExpress your answer in whole dollars (no cents include a leading dollar sign ($inyour answer

User Cfs
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1 Answer

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Let x and y represent the price of two pieces of production equipments.

Given;

Two pieces of production equipment for a factory were purchased for a total of

$2000.


x+y=2000------1

If one piece cost $810 more than the other;


x-y=810-------2

We now have a simultaneous equation.

Solving for x and y. let us Add equation 1 to 2 to eliminate y;


\begin{gathered} x+x+y-y=2000+810 \\ 2x=2810 \\ x=(2810)/(2) \\ x=1405 \end{gathered}

Let us substitute the value of x into equation 1 to get y;


\begin{gathered} x+y=2000 \\ 1405+y=2000 \\ y=2000-1405 \\ y=595 \end{gathered}

Therefore, the price of the less expensive piece of equipm

User Chakshu
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