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What is the dimensions of the entire figure on an area of 132 square inches?

1 Answer

5 votes

Let the length of the given figure is: L=8+x

And the width is: W= 3+x

As it isa square:

So:


\begin{gathered} (8+x)(3+x)=132 \\ 24+8x+3x+x^2=132 \\ x^2+11x+24-132=0 \\ x^2+11x-108=0 \end{gathered}

User Giorgio Minardi
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