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If ABCD is dilated by a factor of 3, thecoordinate of C' would be:6ол5С43B2. 1-6 -5 4-3 -2 -1 012 345-1NOADC' = ([?], [ 12.3

If ABCD is dilated by a factor of 3, thecoordinate of C' would be:6ол5С43B2. 1-6 -5 4-3 -2 -1 012 345-1NOADC-example-1
User Eric White
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1 Answer

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From the question provided, if every coordinate on the quadrilateral is dilated by a factor of 1/2, then the coordinates of every point would be multiplied by 1/2.

Therefore, using the factor of 1/2 to dilate, the coordinates of pont C would be;


\begin{gathered} C=(2,4) \\ \text{Dilated by }(1)/(2); \\ C^(\prime)=(2*(1)/(2),4*(1)/(2)) \\ C^(\prime)=(1,2) \end{gathered}

ANSWER:

The coordinates of C' would therefore be;


C^(\prime)(1,2)

User Viktor Apoyan
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