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What is the powder in watts, P, if the voltage is 850 and the resistance is 170?

What is the powder in watts, P, if the voltage is 850 and the resistance is 170?-example-1
User Ivva
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1 Answer

3 votes

Solution

From the question


V=\sqrt[]{PR}

We are given V = 850 volt and R = 170 ohms

We want to find P


\begin{gathered} V=\sqrt[]{PR} \\ \text{Square both sides} \\ V^2=PR \\ \text{Divide both sides by R} \\ (V^2)/(R)=P \\ \text{Thus,} \\ P=(V^2)/(R) \end{gathered}

Substituting


\begin{gathered} P=(V^2)/(R) \\ P=((850)^2)/(170) \\ P=4250\text{watts} \end{gathered}

Therefore, the power is


P=4250\text{watts}

User Lasf
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