Given:
Working together, it takes two computers 5 minutes to send out a company's email. If it takes the slower computer 15 minutes to do the job on its own
Let the faster computer has a rate of x emails per minute
And the slower computer has a rate of y emails per minutes
And let the total mails = z
When the two computers working together, the time taken to send the mails = 5 minutes
So,

And the slower computer 15 minutes to do the job on its own
So,

substitute equation (2) into equation (1)

So, the answer will be:
The faster computer will do the job in a time = 15/2 = 7.5 minutes