We have to find the probability that you are dealt a ten or a black card.
Out of the 52 card deck, there are 26 black cards.
There are also 4 cards that are tens, but there are 2 cards that are both black and tens.
Then, if we define B: the event of a black card and T: the event of a ten, we can calculate the probability of B or T as:

Replacing with the values of the probability (success events divided by the total possible events), we can solve this as:

Answer: the probability of getting a black or a ten is 23/52.