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Hello, needing help solving this problem. There is part 1, 2 3 and 4.

Hello, needing help solving this problem. There is part 1, 2 3 and 4.-example-1
Hello, needing help solving this problem. There is part 1, 2 3 and 4.-example-1
Hello, needing help solving this problem. There is part 1, 2 3 and 4.-example-2
Hello, needing help solving this problem. There is part 1, 2 3 and 4.-example-3
Hello, needing help solving this problem. There is part 1, 2 3 and 4.-example-4
User Plancke
by
4.1k points

1 Answer

5 votes

Given:


\begin{gathered} \text{ Grid 1-}40x^2+40x+100 \\ \\ Grid\text{ }2-x^2 \\ \\ Grid\text{ }3\text{ - x}^2+40x+400 \end{gathered}

Required:

To show how many longer the side length of grid 3

Step-by-step explanation:

Let's find the side length of each box . Since these boxes are square , and area =side2, we can take the square root of the area to find the length of each side factor each equation.


\begin{gathered} 4x^2+40x+100 \\ \\ (2x+10)(2x+10) \\ \\ 2(2x+10) \\ First\text{ box side length :2x+10 meters} \end{gathered}
\begin{gathered} x^2 \\ second\text{ box side length :x meters} \end{gathered}
\begin{gathered} x^2+40x+400 \\ \\ (x+20)(x+20) \\ \\ (x+20)2 \\ \\ Third\text{ box length :x+20} \end{gathered}

so to find how longer the 3rd box length is we subtract third and 2nd

(x+20)-x

=20 meters

Required answer:

=20 meters

User Bazley
by
4.4k points