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Which equation describes a line of symmetry for square ABCD? x = 0 y = x x = -2 y = -2

Which equation describes a line of symmetry for square ABCD? x = 0 y = x x = -2 y-example-1

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The equation of the line is DB from y = mx + b

From the graph y = 0 when x =0

this means y = x

The graph cuts through the origin, Meaning the y -intercept = 0

answer is: y = x

User Andi Gu
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