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write an equation in slope intercept form of the line that passes through the given point point and is parallel to the graph of the given equation(0,0);y=5/8x+6the equation of the line y= ?

1 Answer

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hello

to solve this question, let's write the standard equation of a straight line


\begin{gathered} y=mx+c \\ \end{gathered}
y=(5)/(8)x+6

since, this equation passes the given gpoint and it's parallel to it, we will have to modify our equation


y-y_1=m(x-x_1)+c

the given points are (0, 0)

let's insert it and solve


\begin{gathered} y-0=(5)/(8)(x-0)+6 \\ y=(5)/(8)x+6 \end{gathered}

from the calculation above, the equation of the line is y = 5/8x + 6

User Alesanco
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