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How to answer number 3?What is the pressure of a 8.5 L cylinder filled with 23.5 g of nitrogen gas at a temperature of 298 K?

How to answer number 3?What is the pressure of a 8.5 L cylinder filled with 23.5 g-example-1

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To solve this problem we will use the ideal gas law. The formula is:

P * V = n * R * T

Where P is the pressure of the gas, V is the volume, n is the number of moles of that gas, R is the ideal gas constant and T is the temperature.

We know some of those values.

V = 8.5 L

T = 298 K

R = 0.082 atm*L/(mol*K)

Then, P is our unknown and we can find the number of moles from the mass of nitogren using its molar mass.

P = ?

mass of N₂ = 23.5 g

atomic mass of N = 14.01 amu

molar mass of N₂ = 2 * 14.01

molar mass of N₂ = 28.02 g/mol

n = number of moles of N₂ = 23.5 g/(28.02 g/mol)

n = 0.839 moles

Now we can replace the values in the formula and solve it for P.

P * V = n * R * T

P = n * R * T / V

P = 0.839 moles * 0.082 atm*L/(mol*K) * 298 K/(8.5 L)

P = 2.41 atm

Answer: the pressure is 2.41 atm.

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