1 Answer

Ask a Question

Redhead · Answer 1 · 2024-01-02T08:18:53+0000

If the figure is divided into 6 rectangles, the total area will be as follows:

A= area

Rectangle 1 and 3:

b= 8cm

h= 4cm

$\begin{gathered} A_(R1)=\text{ b}* h \\ A_(R1)=8*4\text{ = 32} \\ A_(R1)=32\operatorname{cm} \\ As\text{ there are two with the same mesures:} \\ A_(R1,3)=2*32\operatorname{cm}=64\operatorname{cm} \end{gathered}$

Rectangle 2 and 4:

b= 8cm

h= 6cm

$\begin{gathered} A_(R2)=\text{ b}* h \\ A_(R2)=8*6\text{ = }48 \\ A_(R2)=48\operatorname{cm} \\ As\text{ there are two with the same mesures:} \\ A_(R2,4)=\text{ 2}*48\operatorname{cm}=96cm^2 \end{gathered}$

Lateral Rectangle:

b= 6cm

h= 4cm

$\begin{gathered} A_(LR)=\text{ b}* h \\ A_(LR)=6*4\text{ = }24 \\ A_(LR)=24\operatorname{cm} \\ As\text{ there are two lateral rectangles:} \\ A_(LR)=2*24\operatorname{cm}=48\operatorname{cm} \end{gathered}$

Total Area (TA):

$\begin{gathered} A_T=A_(R1,3)+A_(R2,4)+A_(LR) \\ A_T=64\operatorname{cm}+96\operatorname{cm}+48\operatorname{cm} \\ A_T=208\operatorname{cm} \end{gathered}$

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions