Question

9. 2 point Divide(b3 - 8b2 - 12b +34) = (b - 9) using long division. Ob3 + b^2 - 3b+ 7/6-9 O b^2 + b -3 + 7/6-9 O 2 b^2 + b - 3 + 61/b-9 O b^2-b + 3 + -7/5-9

Answer 1

We have to divide the polynomials:

`(b^3-8b^2-12b+34)/(b-9)`

We have to find multiples of (b-9) and substract from the polynomial, like this:

`(b^3-8b^2-12b+34)/(b-9)=(b^3-9b^2)/(b-9)+(b^2-12b+34)/(b-9)=b^2+(b^2-12b+34)/(b-9)`
`b^2+(b^2-9b)/(b-9)+(-3b+34)/(b-9)=b^2+b+(-3b+34)/(b-9)`
`b^2+b+(-3b+27)/(b-9)+(7)/(b-9)=b^2+b-3+(7)/(b-9)`

Answer: b^2+b-3+7/(b-9)

`b^2+b-3+(7)/(b-9)`