Question

Use the tables to name the zeros,their multiplicity,and the effect of the multiplicity on the graph. (In the effect boxes it should be either bounces or intersects) SPELL PROPERLY

Answer 1

We have

`x^2(x-1)^4(x+5)`

First we will find the zeros,

for the term x^2

`x^2=0`
`x=0`

for the term (x-1)^4

`(x-1)^4=0`
`x-1=0`

`x=1`

for the terms (x+5)

`x+5=0`
`x=-5`

zeros

x=-5

x=0

x=1

Then with the multiplicity

Because we have a power of 1 in (x+5), x=-5 has a multiplicity of 1

Because we have a power of two in x^2, x=0 has multiplicity 2

Because we have a power of 4 in (x-1)^4, x=1 has a multiplicity of 4

For the effect

x+5 has an odd power the effect will be crosses

x^2 has an even power the effect will be bounces

(x-1)^4 has an even power the effect will be bounces

, x