Question

Find the distance, c, between (2,-1) and (-1, 4) on the coordinate plane. Round to the nearest tenth

Answer 1

c ≈ 5.8 units

Explanation:

Calculate c using the distance formula

d =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

with (x₁, y₁ ) = (2, - 1 ) and (x₂, y₂ ) = (- 1, 4 )

c =
`√((-1-2))^2+(4-(-1))^2`

=
`√((-3)^2+(4+1)^2)`

=
`√(9+5^2)`

=
`√(9+25)`

=
`√(34)`

≈ 5.8 units ( to the nearest tenth )