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Question 1)A line with slope = 6 that passes through the point (3, 1) written in point-slope form is

User Fez
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The equation of a line in slope-intercept form is given as


y-y_1=m(x-x_1)

The slope of the line is 6

Hence, m = 6

Since the line passes through the point (3, 1)

Hence,


x_1=3,y_1=1

Substitute the values into the equation

This gives


y-1=6(x-3)

Simplify the equation


\begin{gathered} y-1=6x-18 \\ y=6x-18+1 \\ y=6x-17 \end{gathered}

Therefore, the equation of the line is


y=6x-17

User Scarl
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