Question

If an electron has an acceleration of 2.33 × 102 m/sec2, what is this value in units of m/min2?

Answer 1

The electron has an acceleration of 838800
`(m)/(min^(2) )`

Step-by-step explanation:

An electron has an acceleration of 2.33*10²
`(m)/(sec^(2) )`

To be able to express in units
`(m)/(min^(2) )`, you must carry out the conversion taking into account that 1
`(m)/(sec^(2) )`= 3600
`(m)/(min^(2) )`. Then you can apply the following rule of three: if 1
`(m)/(sec^(2) )` equals 3600
`(m)/(min^(2) )`, 2.33 * 10²
`(m)/(sec^(2) )` equals how much
`(m)/(min^(2) )`?

`(m)/(min^(2) )=(2.33*10^(2) (m)/(sec^(2) )*3600(m)/(min^(2) ))/(1(m)/(sec^(2) ))`

`(m)/(min^(2) )=838800`

The electron has an acceleration of 838800
`(m)/(min^(2) )`