In the following image we represent the position of the points R and T in the cartesian plane:
To find the distance between the points we draw a right triangle between them:
Where the resulting triangle has legs of measure 1 and 7, and "d" is the distance between the points.
If we call the legs
a=1
and b=7
Using the Pythagorean theorem, the formula to find "d" is as follows:
![d=\sqrt[]{a^2+b^2}](https://img.qammunity.org/2023/formulas/mathematics/college/fny239akkenz2r2eekuhbsx8hiv5x5k3ky.png)
Next, we substitute the values for the legs a and b:
![d=\sqrt[]{1^2+7^2}](https://img.qammunity.org/2023/formulas/mathematics/college/144pdgos28q7dye48rxbpy42gmjajofi1k.png)
and we solve this operations:
![\begin{gathered} d=\sqrt[]{1+49} \\ d=\sqrt[]{50} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jm9go9pxwvlq91vajlxqmxxvfph76baus5.png)
The distance is square root of 50.
If you need it, we can simplify the square root of the answer as follows:
![d=\sqrt[]{50}=\sqrt[]{25*2}=5\sqrt[]{2}](https://img.qammunity.org/2023/formulas/mathematics/college/ljwe385i89p89pls9p7g0m9f69oakzgihg.png)
So the answer is:
![\sqrt[]{50}=5\sqrt[]{2}](https://img.qammunity.org/2023/formulas/mathematics/college/ow95brlzumkl676hbfw63p6x4hbikfj9e0.png)