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7 Given APHS = ACNF, find the values of x, y, and z.F(3y - 1)H (6x - 290°S36°Р115°fc(4z - 32)N

7 Given APHS = ACNF, find the values of x, y, and z.F(3y - 1)H (6x - 290°S36°Р115°fc-example-1
User Kumareshan
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1 Answer

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Here, we have two congruent triangles

Since they are congruent, they have similar and equal angles.

From the diagram, we can see that;

6x - 29 = 115 (They are both topmost angles of both triangles)

Solving this, we have;

6x = 115 + 29

6x = 144

divide both sides by 6

x = 144/6

x = 24°

Furthermore, we can see that;

4z - 32 = 36

4z = 36 + 32

4z = 68

z = 68/4

z = 17°

And lastly;

(3y-1) + 115 + (4z-32) = 180 ( sum of angles in a triangle)

Since z = 17, 4z - 32 will be 4(17)-32 = 68 - 32 = 36

Thus;

3y - 1 + 115 + 36 = 180

3y + 150 = 180

3y = 180 -150

3y = 30

divide both sides by 3

y = 30/3

y = 10°

x = 24° , y = 10° and z = 17°

User Pszaba
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