Question

Solve the quadratic equation by factoring Write the answer in reduced fraction form, if necessary.

Answer 1

Given:

The quadratic equation ,

`42x^2-29x-5=0`

The solution of the given quadratic equation can be obtained as,

`\begin{gathered} x=\frac{-(-29)\pm\sqrt[]{(-29)^2-4(42)(-5)}}{2*42} \\ \text{ =}(29\pm41)/(84) \\ x=(29+41)/(84)\text{ or x=}(29-41)/(84) \\ x=(70)/(84)\text{ or x=}(-12)/(84) \\ x=(10)/(12)\text{ or x=}(-3)/(21) \\ x=(5)/(6)\text{ or x=}(-1)/(7) \end{gathered}`

Hence, the solutions are,

`x=(5)/(6),\text{ }(-1)/(7)`