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Given: AD ⊥DB, BC ⊥CA and AD ≅CB .Prove ΔADB≅ΔBCA

Given: AD ⊥DB, BC ⊥CA and AD ≅CB .Prove ΔADB≅ΔBCA-example-1
User Hawa
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1 Answer

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step 11

Prove

DB=AC

Applying Pythagorean theorem

Right triangle ADB

AB^2=AD^2+DB^2 ------> DB^2=AB^2-AD^2

Right triangle BCA

AB^2=BC^2+AC^2 -----> AC^2=AB^2-BC^2

Remember that

AD=BC

by substitution

AC=DB

step 12

triangle ADB is congruent to triangle BCA by SSS

User Saurabh Ranu
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