Given the functions:
s(x) = 3x - 2
t(x) = 4x
Let's find the following:
• (s + t)(x):
Here we are to add both functions together
(s + t)(x) = (3x - 2) + 4x
= 3x - 2 + 4x
= 3x + 4x - 2
= 7x - 2
• (s * t)(x):
Here, we are to multiply both functions
(s * t)(x) = (3x - 2)(4x)
= 3x(4x) - 2(4x)
= 12x² - 8x
• (s - t)(-2):
Here, let's subtract both functions and input -2 for x.
s(-2) - t(-2) = (3(-2) - 2)) - (4(-2))
= (-6 - 2) - (-8)
= ( -8) - (-8)
= -8 + 8 = 0
ANSWER:
(s + t)(x) = 7x - 2
(s * t)(x) = 12x² - 8x
(s - t)(-2) = 0