Question

Your Equation:Your Equation:5. Find the possible equation of the third degree polynomial with:a single root at x = -2, a double root at x = 4Equation:

Answer 1

ANSWER;

x³ - 6x² + 32

Step-by-step explanation:

Given the rrots:

x = -2

x = 4

Thus we have the factors:

x = -2 ==> (x + 2) single root

x = 4 ==> (x - 4)(x - 4) double root

We have:

(x + 2)(x - 4)(x - 4)

= (x + 2)(x² - 8x + 16)

Expand:

= x*x² - x*8x + x*16 + 2*x² - 2*8x + 2*16

= x³ - 8x² + 16x + 2x² - 16x + 32

Collect like terms:

= x³ - 8x² + 2x² + 16x - 16x + 32

= x³ - 6x² + 32

Therefore the possible equation = x³ - 6x² + 32

ANSWER:

x³ - 6x² + 32