Question

In the figure, KM is perpendicular to JL Point Pis the midpoint of JL.KMGiven AJPKALPK and AJPM - ALPM, which criterion can be directly applied to show that AKIM AKLM?CAGReview progres

Answer 1

In this problem we have that

JK=KL

JM=LM

and

KM is a common side

therefore

triangle KJM and triangle KLM are congruent by SSS