In the given data :
![\text{ The volume of the rectangular box with squre base is V = L}^2H](https://img.qammunity.org/2023/formulas/mathematics/high-school/pyyj7ae36gpegzzv5x1fs7nzami2zu0rh9.png)
where L is the length and H is the height.
For the 4 foot tall cardoard box,with the square base has length = 2feet
The volume of the carboard is describe as :
![\text{ Volume = L}^2H](https://img.qammunity.org/2023/formulas/mathematics/high-school/d66z274buzzlrnnfnv97tjpr7fj7276ahd.png)
here we have, length = Square length = 2 feet
Breadth = Height of the cardboard = 4 foot
Substitute the value and simplify:
![\begin{gathered} \text{ Volume = L}^2H \\ \text{ Volume=2}^2*4 \\ \text{Volume = 4}*4 \\ \text{Volume =16 f}eet^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ied0pm7qdia0t9y2kw8rvg2dtxh2kskuq3.png)
So, the volume of cardboard is 16 feet³
Answer : Volume of cardboard is 16 feet³