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44. Find the odds in favor of a win for a team with a recordof 21 wins and 6 losses.odds in favor =

User Jisson
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1 Answer

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The number of wins that the team recorded is 21

The number of losses is 6

Odds are the combinations of the event that you want divided by the event of it not hapenning

The events that we want are wins = 21

the events that we don't want(That don't go in our favor) = 6

Thus,

Odds = P(win)/P(loss)

P(win) = 21/(21 + 6) = 21/27

P(loss) = 6/(21 + 6) = 6/27

odds in favor = (21/27) / (6/27)

odds in favor = 21/27 x 27/6 = 21/6

odds in favour = 3.5

User Schmijos
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