Question

A miniature light bulb with a resistance of 6 ohms is connected to a 12-volt source. How much current will flow through the bulb?A) 6 ampsB) 2 amps C) 8 ampsD) 4 amps

Answer 1

`I=2\text{ amps}`

Explanation:

This situation is represented by Ohm's Law, it can be used to find individual currents, voltages, and resistances. It is represented by the following equation:

`\begin{gathered} V=IR \\ \text{where,} \\ V=\text{Voltage} \\ I=\text{Current} \\ R=\text{ Resistance} \end{gathered}`

Since, it has a resistance of 6 ohms and has a voltage of 12-volt, isolate I and solve for the current:

`\begin{gathered} I=(V)/(R) \\ I=(12)/(6) \\ I=2\text{ amps} \end{gathered}`